本文最后更新于 463 天前，其中的信息可能已经有所发展或是发生改变。
一定要坚持下去，别像蓝桥杯一样了，哎 一定要克服懒惰。
L1-002 打印沙漏
少过一个样例，懒得调试了
#include <bits/stdc++.h>
using namespace std;
int s[25] = {1, 7, 17, 31, 49, 71, 97, 127, 161, 199, 241, 287, 337, 391, 449, 511, 577, 647, 721, 799, 881, 967};
int main()
{
int n;
char word;
cin >> n >> word;
int t, tindex = 0;
for (int i = 0; i < 23; i++)
{
if (n >= s[21])
{
t = s[i];
tindex = 21;
// cout << t;
break;
}
if (n >= s[i] && n < s[i + 1])
{
t = s[i];
tindex = i;
// cout << t;
break;
}
}
int maxx = (tindex + 1) * 2 - 1;
int max2 = (tindex + 1) * 2 - 1;
int spacenum = 0;
for (int i = 1; i <= maxx; i++)
{
// cout << spacenum << max2;
if (i <= tindex)
{
for (int k = 0; k < spacenum; k++)
printf(" ");
for (int j = 1; j <= max2; j++)
printf("%c", word);
puts("");
spacenum++;
max2 -= 2;
}
else
{
for (int k = 0; k < spacenum; k++)
printf(" ");
for (int j = 1; j <= max2; j++)
printf("%c", word);
puts("");
spacenum--;
max2 += 2;
}
}
cout << n - t;
return 0;
}L1-003 个位数统计
n = input()
l = {}
for i in n:
if i not in l:
l[i] = 1
else:
l[i] += 1
l = sorted(l.items())
# print(l)
for i in l:
print("{}:{}".format(i[0], i[1]))
L1-005 考试座位号
#include <bits/stdc++.h>
using namespace std;
struct node
{
long long id;
int one;
int two;
} a[1007];
int main()
{
int x[1007];
int n;
cin >> n;
for (int i = 0; i < n; i++)
{
cin >> a[i].id >> a[i].one >> a[i].two;
}
int t;
cin >> t;
for (int i = 0; i < t; i++)
{
cin >> x[i];
}
for (int i = 0; i < t; i++)
{
for (int j = 0; j < n; j++)
{
if (x[i] == a[j].one)
{
printf("%lld %d", a[j].id, a[j].two);
puts("");
break;
}
}
}
return 0;
}
L1-009 N个数求和
一开始竟然有转化成小数做的冲动。。。。。
#include <bits/stdc++.h>
using namespace std;
int gcd(int a, int b)
{
return b ? gcd(b, a % b) : a;
}
struct node
{
int zi;
int mu;
} a[1000], ans;
int main()
{
int n;
cin >> n;
for (int i = 0; i < n; i++)
scanf("%d/%d", &a[i].zi, &a[i].mu);
ans = a[0];
for (int i = 1; i < n; i++)
{
ans.zi = ans.zi * a[i].mu + a[i].zi * ans.mu;
ans.mu *= a[i].mu;
int g = gcd(ans.zi, ans.mu);
if (g != 1)
{
ans.zi /= g;
ans.mu /= g;
}
}
// cout << ans.zi << " " << ans.mu;
int z = ans.zi / ans.mu;
int f = ans.zi % ans.mu;
if (z != 0 && f != 0)
cout << z << " " << f << "/" << ans.mu;
else if (z == 0 && f == 0)
cout << 0;
else if (z != 0 && f == 0)
cout << z;
else if (z == 0 && f != 0)
cout << f << "/" << ans.mu;
return 0;
}L1-011 A-B
a = input()
b = input()
for i in a:
if i not in b:
print(i, end="")
L1-015 跟奥巴马一起画方块
#include <bits/stdc++.h>
using namespace std;
int gcd(int a, int b)
{
return b ? gcd(b, a % b) : a;
}
struct node
{
int zi;
int mu;
} a[1000], ans;
int main()
{
int n, n2;
char c;
cin >> n >> c;
n2 = n;
if (n & 1)
n = n / 2 + 1;
else
n /= 2;
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n2; j++)
{
cout << c;
}
puts("");
}
return 0;
}L1-016 查验身份证
明明都是些简单题，但是我总是会出些奇奇怪怪的bug我真是太久没刷题了
n = int(input())
l = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2]
d = {0: '1', 1: "0", 2: 'X', 3: "9", 4: "8",
5: "7", 6: "6", 7: "5", 8: "4", 9: "3", 10: "2"}
ans = []
sum = 0
flag = False
for i in range(n):
sum = 0
flag = False
t = input()
for i in range(17):
if t[i] < '0' or t[i] > '9':
ans.append(t)
flag = True
break
if flag == True:
continue
for i in range(17):
sum += int(t[i])*l[i]
# print("{}*{}={}".format(int(t[i]), l[i], int(t[i])*l[i]), end=" ")
# print(sum)
index = sum % 11
# print(index)
if d[index] != t[17]:
ans.append(t)
if ans:
for i in ans:
print(i)
else:
print("All passed")
#include<bits/stdc++.h>
using namespace std;
int x[100000];
int main()
{
string a;
cin>>a;
for(char i:a)
{
// cout<<i<<" ";
x[i]++;
}
x['G']+=x['g'];
x['P']+=x['p'];
x['L']+=x['l'];
x['T']+=x['t'];
char t[4]={'G','P','L','T'};
// cout<<x['G']<<x['P']<<x['L']<<x['T'];
while(true)
{
for(char i:t)
{
if(x[i]>0)
{
cout<<i;
x[i]--;
}
}
if(x['G']==0&&x['P']==0&&x['L']==0&&x['T']==0)break;
}
}n=input()
sum=1
l=0
if n[0]=='-':
sum*=1.5
l=len(n)-1
if int(n)%2==0:
sum*=2
if n[0]!='-':
l=len(n)
num=0
for i in n:
if i=='2':
num+=1
print("{:.2f}%".format(float(num)/l*sum*100))
L2-002 链表去重
只过了15分/(ㄒoㄒ)/~~ 呜呜呜
l2 有点东西 难不成让我真写一个链表
白瞎我写那么长时间
#include <bits/stdc++.h>
using namespace std;
struct node
{
int val;
int next;
};
const int N = 10000000;
struct node a[N];
struct node b[N];
int x[N];
int main()
{
int head, n;
cin >> head >> n;
for (int i = 0; i < n; i++)
{
int ad, va, ne;
cin >> ad >> va >> ne;
a[ad].val = va;
a[ad].next = ne;
}
int idx = head;
int head2=-1; // 链表b的头结点
int flag = 0; // 0表示b链表还为空
int temp;
int t = 0; // 被删除节点的个数
while(idx!=-1)
{
x[abs(a[idx].val)] = 1;
if (x[abs(a[a[idx].next].val)] != 0) // 这个if里的a[idx].next指的是被删除节点的地址
{
if (flag == 0) // 第一个被删除的节点，作为b链表的头结点
{
head2 = a[idx].next;
b[a[idx].next].val = a[a[idx].next].val;
b[a[idx].next].next = -1; // 他是头结点,next先指向空
temp = head2; // 标记指针用来尾插
flag = 1;
}
else
{
b[a[idx].next].val = a[a[idx].next].val;
b[temp].next = a[idx].next;
temp = a[idx].next;
b[temp].next=-1;
}
t++;
a[idx].next = a[a[idx].next].next; // 删除节点
}
// cout << idx << " " << a[idx].val << " " << a[idx].next<<endl;
idx = a[idx].next;
}
idx = head;
while(idx!=-1)
{
if(a[idx].next!=-1)
{
printf("%05d %d %05d\n",idx,a[idx].val,a[idx].next);
}
else{
printf("%05d %d -1\n",idx,a[idx].val);
}
// cout << idx << " " << a[idx].val << " " << a[idx].next << endl;
idx = a[idx].next;
}
if(head2!=-1)
{
idx=head2;
while(idx!=-1)
{
if(b[idx].next!=-1)
{
printf("%05d %d %05d\n",idx,b[idx].val,b[idx].next);
}
else{
printf("%05d %d -1\n",idx,b[idx].val);
}
// cout << idx << " " << b[idx].val << " " << b[idx].next << endl;
idx = b[idx].next;
}
}
}